Mathematics
9 Online
OpenStudy (anonymous):
cos(-247.5 DEGREES)
IN EXACT VALUE.
solve using half angle formula.
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OpenStudy (inkyvoyd):
Hm.
OpenStudy (inkyvoyd):
add 360 degrees.
OpenStudy (inkyvoyd):
tell me what you get.
OpenStudy (anonymous):
112.5
OpenStudy (inkyvoyd):
Now double that value!
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OpenStudy (anonymous):
ohh so cos 225 - sqroot 2 over 2?
OpenStudy (inkyvoyd):
You know the half angle formula?
OpenStudy (inkyvoyd):
I forgot it, but I can derive it on spot :D
OpenStudy (anonymous):
yes cos u/2 = sqroot 1 + cos u/2
OpenStudy (inkyvoyd):
Yep.
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OpenStudy (inkyvoyd):
So, you should be fine. If you want to check your work, go to wolfram alpha, and just type in the cos(blah)
OpenStudy (anonymous):
I have tried that on both wolfram and my calculator I get an exact amount
OpenStudy (inkyvoyd):
You get an exact amount, or you want one but they dont' give one?
OpenStudy (anonymous):
i got the problem wrong... i got sqroot 2+sqroot2 all over 2
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OpenStudy (anonymous):
but it's wrong
OpenStudy (inkyvoyd):
Ok, lemme do some math
OpenStudy (inkyvoyd):
That's probaly a quadrant eror.
OpenStudy (inkyvoyd):
And, @lgbasallote
OpenStudy (lgbasallote):
someone called?
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OpenStudy (inkyvoyd):
Helpy out?
OpenStudy (lgbasallote):
hmmm this seems difficult -__-- that or i just forgot my trig
OpenStudy (inkyvoyd):
Add 360 derees, then use 225 as the angle to find half of.
OpenStudy (inkyvoyd):
-247.5 bro.
OpenStudy (anonymous):
\[
t =247.5 \\
2t= 495= 360 + 90 +45 \\
\cos(2t) =\ cos(90 + 45)=-\cos(45) = -\frac 1{\sqrt 2}\\
\cos^2(t)=\frac{ 1+ \cos(2t)}2=\frac {1-\frac 1{\sqrt 2}} {2}=\\
\frac{1}{2}-\frac{1}{2
\sqrt{2}}\\
\cos(t) = \pm \sqrt{\frac{1}{2}-\frac{1}{2
\sqrt{2}}}
\]
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OpenStudy (anonymous):
\[ \cos(t) = \cos(247.5)= -\sqrt{\frac{1}{2}-\frac{1}{2
\sqrt{2}}}= -0.382683
\]