Question

HELP ME PLZ??

Answer 1

\[\frac{1(x+3)(x+6) + 2(x)(x+6) + 3(x)(x+3)}{(x)(x+3)(x+6)} = 1\]

Answer 2

i have to find x.. it says there are 3 possible values for x

Answer 3

yes you get a cubic equation when you solve this

Answer 4

\[x(x+3)(x+6)=6x^2+30x+18\]

Answer 5

\[x^3+3 x^2-12 x-18 = 0\] is the equation you have to solve

Answer 6

thanks!!!

Answer 7

you can check that one of the roots is 3, then the other two you can find using the quadratic formula once you factor out
\[x^3+3 x^2-12 x-18 =(x-3)(x^2+6x+6)\]