Ask your own question, for FREE!
Mathematics 26 Online
OpenStudy (anonymous):

How do you integrate absolute value functions?

OpenStudy (anonymous):

divide into the two cases where \(f(x)>0\) and where \(f(x)<0\)

OpenStudy (anonymous):

You split the absolute value equation into two equations?

OpenStudy (anonymous):

an example would be great

OpenStudy (apoorvk):

Integrate them by breaking them into parts, one from where the function is positive originally, and the other by applying a negative sign to that part of the limits where the function is negative ('cause the graph is flipped from that point)

OpenStudy (anonymous):

\[\int_{-1}^5|x-3|dx=\int_{-1}^3(3-x)dx+\int_3^5(x-3)dx\] for example

OpenStudy (anonymous):

easy example since \[f(x) = |x-3| = \left\{\begin{array}{rcc} 3-x & \text{if} & x <3 \\ x-3& \text{if} & x \geq 3 \end{array} \right.\]

OpenStudy (anonymous):

What about 2x from -2 to 4?

OpenStudy (anonymous):

@Romero Do you mean integration of |2x| from -2 to 4??

OpenStudy (anonymous):

Well year we are talking about absolute values here right?

OpenStudy (anonymous):

From here we see that we will have to integrate from -2 to 0 with the equation-1/2 x and 2x from 0 to 4 Note how we inversed the slope.

OpenStudy (anonymous):

wait..why is it when x is greater than or less than 3

OpenStudy (anonymous):

|x−3|

OpenStudy (anonymous):

Well, in that case it is \[2 \int\limits_{-2}^{4} |x|\] f(x) = x for x > 0 = - x for x<0 Substituting this we get. \[2 \int\limits_{-2}^{0} (-x) + 2 \int\limits_{0}^{4} x\] rest you can solve :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!