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Mathematics 27 Online
OpenStudy (anonymous):

calling all word problem lovers! Sam has $0.93 in a total of nine coins. She does not have a half dollar. How many of each coin does she have? Pennies, nickels, dimes, quarters

OpenStudy (anonymous):

keep in mind that we can use two quarters or five dimes because Sam does NOT have $0.50

OpenStudy (anonymous):

She must have 3 pennies since there is no other way to represent $.01. This leaves 6 coins to make $.90. If we use two quarters as well, we have accounted for $.53, which leaves us with $.40 to account for. For this we can use four times. Her coins are 3 pennies, 4 dimes, and 2 quarters. 3 + 4 + 2 = 9 coins .03 + .40 + .50 = .93

OpenStudy (anonymous):

Sam does NOT have $0.50

OpenStudy (anonymous):

A half dollar is another kind of coin. Are you sure the problem is just not ruling out that sort of coin as an option?

OpenStudy (anonymous):

it is? really?

OpenStudy (anonymous):

Mmhm. Don't see them a lot these days, though. I'm not sure of any other way to come up with her coinage.

OpenStudy (anonymous):

okay. thank you!!!!!

OpenStudy (anonymous):

wait, how many nickel would be used though?

OpenStudy (anonymous):

lol, 50 cent coin, can we also use sacajawea dollars

OpenStudy (anonymous):

We don't need to use any nickels. We would have to use at least ten coins for that (3 pennies, 2 nickels, 3 dimes, 2 quarters, because 2 nickels replaces one dime).

OpenStudy (anonymous):

okay thanks again

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