Question

integrate x sin (2x^2) dx

Answer 1

u-sub,
u=2x^2
du=4xdx
\[\text{}=\frac{1}{4}\int\limits \sin (u) \, du\]
solve

Answer 2

\[-\frac{\cos (u)}{4}+c\]
\[-\frac{1}{4} \cos \left(2 x^2\right)+c\]

Answer 3

integrate x sin (2x^2) dx
=integrate sin (2x^2) d(1/2)x^2)
=(1/2)(1/2)integrate sin(2x^2)d(2x^2)
=-1/4 cos(2x^2) +C

Answer 4

got it. thank you