Question

Please Help me.. I don't understand it.
2. (3x^2-7x-6)/(x-3)

Answer 1

Factor the numerator.

Answer 2

I got (3x^2) (-9+x) (x+2)/(x-3) :: Do i now divide by 3

Answer 3

\[ {3x^2 - 7x -6}\over{x-3}\]
\[={{3x^2 - 9x + 2x - 6}\over{x-3}}={{{3x(x-3)+2(x-3)}}\over{x-3}}\]
\[={{(3x+2)(x-3)}\over{x-3}}\]

Answer 4

Thank You. SoMuch..

Answer 5

hey alice first term of numerator is 3x^2 and last term is 6
multiply the coefficient of first and last term 3*6 = 18
now factorize 18 = 2 * 9
the middle term should be further written as (-9x+2x) = -7x
3x^2 - 7x - 6 = 3x^2 -9x +2x-6 = 3x(x-3)+2(x-3) = (x-3)(3x+2)

Answer 6

My process was right just messed up on the (3x^2) (-9+x) (x+2)/(x-3) it was suppose to be 3x^2 -9x +2x-6 . Thank you again.