Question

Solve 4y^3-36y=0

Answer 1

First factor you 4y

Answer 2

factor out 4y I meant to type.

Answer 3

(2y-6)(2y+6)=0

Answer 4

y(2y-6)(2y+6)=0

Answer 5

1. factorise the equation on the left.
4y^3-36y=0
4y (y^2 -9) =0
4y (y-3)(y+3) =0
2. put each factor =0
4y=0 (y-3) =0 (y+3) =0
3. Solve them :)

Answer 6

No @cinar

Answer 7

4y(y^2)-9 = 0

4y(y+3)(y-3)

y=0 OR y=-3 OR y=3

Answer 8

why not..

Answer 9

It's right @cinar

Answer 10

can someone solve 4x^3-x=0

Answer 11

x(4x^2 - 1)= 0

x = 0 or 4x^2 -1=0

(2x-1)(2x+1)=0

x= -1/2 OR x = 1/2

So the answer is :
x=0
x= -1/2
x= 1/2

Answer 12

@yarely