Question

Trig help?
1. Solve for x. sqrt 2x+3 = sqrt 6x-1
2. Solve for b. b^4/25=4

Answer 1

1. \[\sqrt{2x+3} = \sqrt{6x-1}\]

2.
\[\sqrt{b^4/25} = 4\]

Answer 2

for the first one square both sides...
you'll get
2x+3=6x-1

... can you finish the first one now ? :)

Answer 3

2x-6x=-1-3
-4x=-4 we multiply both sides by -1
4x=4
x=4/4
x=1

Answer 4

is it 1??

Answer 5

yes it is.. well done. For the second one I'll give you a hint... let's see what you can do :)

Answer 6

\[\large \sqrt{\frac{b^4}{25}}=4\]
\[\large \frac{\sqrt{b^4}}{\sqrt{25}}=4\]
\[\large \frac{b^2}{5}=4\]
can you do it now ? :)

Answer 7

is it +/- 2 √5 ??

Answer 8

yes it is... well done :)

Answer 9

Thank you so much!!! :)

Answer 10

My pleasure ..