Question

During a physics demonstration, a fully charged 98-µF capacitor is discharged through a 125-Ω resistor. How long will it take for the capacitor to lose 75% of its initial energy?
Given that:

U=(q^2) / 2C

q= C*V (1- e^(-t/RC) )


U: is the capacitor's energy
C: is the capacitance
R: is the resistance
q: is the capacitor's charge

Answer 1

i need the answer of this one too

Answer 2

:(

Answer 3

r u from BUE ??

Answer 4

Yeah

Answer 5

And apparently u r from there as well

Answer 6

3erefty t7eleha ??? :(

Answer 7

la2 lessa

Answer 8

Hi @Esraa Energy stored in a capacitor is given as
\[\frac{1}{2} Q^2/ C\]
\[q= C*V (1- e^{(-t/RC)} )\]
Are you here?

Answer 9

esraa hatb2a 8.5 ms :)

Answer 10

@Esraa are you here?

Answer 11

Yeah

Answer 12

Thnx @marwa.ally =)

Answer 13

Did you understand?

Answer 14

me 2 from bue :D

Answer 15

@ash2326 it is direct substitution, right?

Answer 16

Yeah but first we need to find the charge when the capacitor has lost 75% of energy, Can you find that?