Question

if you start at the number 15 and there are three missing numbers and the fourth number ids 355 , what is the pattern , and the three missing numbers.

Answer 1

please help

Answer 2

if the numbers are in an arithmetic progression, then there will be a constant difference between each one - call that 'd'. so the number we have form this sequence:
15,
15+d,
15+2d,
15+3d,
15+4d = 355

use the last expression to work out the value for 'd' which will then allow you to work out the three missing numbers.

Answer 3

please can you just tell me the pattern and i'l do the rest myself.

Answer 4

please @asnaseer

Answer 5

I've shown you what to do above ^^

Answer 6

solve the following to find 'd':\[15+4d=355\]

Answer 7

'd' represents the difference between each term of sequence - that is your 'pattern'

Answer 8

thank you very much

Answer 9

yw

Answer 10

I see you haven't closed this question yet - are you still stuck? I thought you understood now how to solve it?

Answer 11

i don't get it

Answer 12

ok - let me try to explain step-by-step...

Answer 13

you are given the first number: 15
and you are given the last number: 355

Answer 14

you are also told that there are three numbers inbetween

Answer 15

k

Answer 16

so lets say the difference between each of these numbers remains the same - i.e. they form an arithmetic sequence - do you know what that is?

Answer 17

no

Answer 18

an arithmetic sequence is one where you have a sequence of numbers where the difference between each successive number is the same.

e.g. the sequence: 2, 7, 12, 17, ...

is an arithmetic sequence because you just add 5 each time to get from one term to the next.

Answer 19

make sense?

Answer 20

yes

Answer 21

later you should check some web sites to become more familiar with this if you want, e.g. try this one: http://www.basic-mathematics.com/arithmetic-sequence.html

Answer 22

now, in your problem, you are given the first and last numbers of this sequence and you are told that there are 3 missing numbers in between

Answer 23

now what I did was use a variable 'd' to represent the difference between each term.

Answer 24

we need to work out what this common difference is

Answer 25

understand?

Answer 26

okay

Answer 27

so, if the difference between each of our terms is 'd', then we know we can write the sequence as:

15, <--- 1st term
15 + d, <--- 2nd term
15 + d + d , <--- 3rd term
15 + d + d + d, <--- 4th term
15 + d + d + d + d <--- 5th term

Answer 28

because each time we add on another 'd' to get to the next term - understand?

Answer 29

if it helps, we can look at the example sequence we saw above: 2, 7, 12, 17, ...
this we said had a difference of 5 between each term, so it can be written as:

2,
2 + 5 (=7),
2 + 5 + 5 (=12),
2 + 5 + 5 + 5 (=17),
...

Answer 30

do you understand so far?

Answer 31

hello? if you don't reply then it is very difficult to help...

Answer 32

yeah so sorry about that

Answer 33

i really get it now .

Answer 34

ok - so no more explanation required?

Answer 35

yeah