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if log base b a=0.24 then log base b times (ab^2) is equal to
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\[\log_{b} a = 0.24\] then \[\log_{b} (ab^2)\] is equal to
\[\log_b(ab^2)=\log_b(a)+\log_b(b^2)\] can you finish from there?
so u add a and b?
you are given \(\log_b(a)=.24\) right? how about \(\log_b(b^2)\)?
u dont know b?
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no it doesn't matter what b is
\[\log_b(b^n)=n\]
so it equal to 2?
yes, it is 2 well your answer is \(2.24\)
so 2.24 is ur final answer
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yes
can u help me with a couple more questions also? please?
if a= b ^ (clog base b times d) then which of the following must be true?
\[a=b^\[c \log_{b} d\]
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