Given the triangle below, what is sec ∡B? a. 4 sqrt33/33 b. 7/4 c. 4/7 d. 7 sqrt33/33

Question

Given the triangle below, what is sec ∡B?                         a. 4 sqrt33/33                                                                 b. 7/4                                                                           c. 4/7                                                                         d. 7 sqrt33/33

anonymous · Answer

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anonymous · Answer

Sec B = 1/ Cos B
and cosB = A/7
so sec B = 7/A

where A = $$\sqrt{7^2 - 4^2}$$

anonymous · Answer

Seriously? you can do the rest with a calculator.