Question

Given the triangle below, what is sec ∡B? a. 4 sqrt33/33 b. 7/4 c. 4/7 d. 7 sqrt33/33

Answer 1

Sec B = 1/ Cos B
and cosB = A/7
so sec B = 7/A

where A = \[\sqrt{7^2 - 4^2}\]

Answer 2

Seriously? you can do the rest with a calculator.