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for set A={1/n:n is positive integer}, why its limit point is {0} ?
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Because the limit of its associated function, \(\large f(x)=\frac{1}{x}\), as x approaches infinity is 0.
how to explain if based on the definition of limit point?
Its limit is 0 because for an arbitrary \(\epsilon\) there exists an integer \(n_0\) such that \[n>n_0 \Rightarrow \left | \frac{1}{n}\right |<\epsilon\]. If I recall correctly, \(\LARGE n_0=\frac{1}{\epsilon}\).
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