Question

solution set for the equation
-2x^2+8x-8=0
A) {-2}
B) {2}
C) {-2,2}
J) {-2, 0, 5}

Answer 1

D*

Answer 2

definitely not D

Answer 3

you have a polynomial of degree two (quadratic) and it can have at most 2 zeros, not 3
also notice that if you replace x by 0 you do not get 0, you get -8

Answer 4

do you know how i can get the answer?

Answer 5

you could use the quadratic formula
\[x=\left( \left( -b \pm \sqrt{b ^{2}-4ac} \right)\over 2a \right)\]where\[y=ax ^{2}=bx=c\]

Answer 6

No I meant
\[ax ^{2}+bx+c=0\]

Answer 7

I guess I'm getting tired and making silly mistakes.

Answer 8

thank you :D

Answer 9

you're welcome.

Answer 10

is that possible with that becuase the number inside the radical is negative D: