Essay; show all work. A simple dartboard has three areas… the main board has a radius of 8 inches, there is a circle with a radius of 6 inches, and the bullseye has a radius of 4 inches. What is the probability of a random dart landing inside the bullseye?
from what i am reading onling you Pi * 4(2) ________ pi* 8(2) which equals 16/64=1/4 or 25% but how are they doing this?
is there a formula i cannot find?
You might have to assume that the dart its the board , the sum of probabilities is 1, i guess the probability of landing inside one area is proportional to its relative area on the whole board
the answer seems to be correct, but what i dont understand is how does pi *4(2) squared ------------ pi * 8(2) squared = 16/64=1/4 wouldnt you multiply pi to them insteasd of just squaring 4 and 8?
the area of a circle \[A=\pi r^2\] for a radius of 4 \[A_{Bulls Eye}=\pi(4)^2=16\pi\] for a radius of 8 \[A_{Board}=\pi(8)^2=64\pi\] the ratio of the bulls eye to the total board is \[\frac{A_{Bulls Eye}}{A_{board}}=\frac{16\pi}{64\pi}=\frac{ 1}{ 4}\]
Are you are those measurements are of the radius? a one in four chance of bulls eye seems too large to me , perhaps the measurements are of the diameter?
Essay; show all work. A simple dartboard has three areas… the main board has a radius of 8 inches, there is a circle with a radius of 6 inches, and the bullseye has a radius of 4 inches. What is the probability of a random dart landing inside the bullseye? Round to the nearest thousandth. (Hint: Use A=pir2
ok so it just an easy dart board with a huge bulls eye
Must be lol but thank you so much for your help!! its so appreciated!
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