Question

ken has three more coins that twice the number javier has. khald has 5 fewer coins than javier. they have 50 coins together

Answer 1

how can i do this

Answer 2

Let j= the number of coins Javier has, let k= the number of coins Ken has, and Let x= the number of coins khald has.

Firstly, j+k+x=50.

Next, 2j+3=k. Finally j=x+5.

To solve a 3 equation system you must use substitution. First step: choose two equations that you have known values for. Let's chose the last two equations. Since we know j=x+5, we can substitute it into the first of the later, 2(x+5)+3=k. FInally we know k and j so we can substitute these into the first equation to find x.

(x+5)+2(x+5)+3+(x)=50

Now simplify to find x.

x+5+2x+10+3+x=50.

4x+18=50

4x=32
x=8

Substitute 8 back into the other equations. j=8+5; j=13.

2(13)+3=k. k=29.

Khald has 8 coins, Javier has 13 coins, and Ken has 29 coins. Done :)

Answer 3

thank u s0 much

Answer 4

No problem would you mind rating me the best answer? :)

Answer 5

where can i do that

Answer 6

on my reply click best answer, top right