Find an equation of the line through A (-6, 5) having slope 7
In the slope-intercept form, plug (x,y) in to find the equation.
General equation of a straight line. Either y=mx+c or (y-y1)=m(x-x1) Slope 7 therefore substitute 7 into the equation as m. Then put in x and y.
The slope-intercept being \[y=mx+b\]\[5=(7(-6)+b\]
but in this question only one point given?
Yes, but you have the slope.
You only need a point and a slope to find a straight line function.
so I use this formula for finding equation of line : y=mx+b? Or I can also use this one y-y1 = m (x-x1) ?
Either is acceptable, but you generally use the 1st if you've just started doing this sort of stuff.
E.g.: I have a function g Its slope is 0 and passes by the origin |dw:1336080066663:dw| You plug everything in the equation to find the x-intercept \[f(g)=mx+b\]\[0=0x+b\]\[b=0\] \[f(g) = 0x + 0\]\[f(g)=x\] The formula \[\large m= \frac{y_{2} - y_{1}}{x_{2}-x_{1}},~~m=slope\] is usually used when you want to find the slope with 2 points given.
Thanks zepp I only just need to plug the values or do simplification in it?
Yes, what I did above is to find the y-intercept, you already have the slope. Remember, a straight line function is defined by 2 things: the slope and the y-intercept
So I don't need more simplication, that's my answer ?
y=mx+b 5=7(-6)+b ?
Yes! ;D
The reason why you use y-y1 etc is because that is the totally general formula. You will notice sonner or later that y=mx+c does not work for vertical lines etc. Also it is easier to manipulate in some circumstances
Find 'b'
Thank you, and sorry my English is not good.
my contribution is this: \[y-y_o=m(x-x_o)\] \[y=y_o=mx-mx_o\] \[y=mx-mx_o+y_o\] \[y = mx+b; \ b=y_o-mx_o\]
got a spurious "=" in there
lol two equals
:) the point is; you dont have to resolve for b, its already there
it means b = 7(-6) +5
and now if I solve it, I will find the interecpt ?
\[y=mx-mx_o+y_o\] \[y=7x-7(-6)+5\]
but y is given in this question?
xo and yo are given; not x and y x and y are generic points for input and output of the equation itself xo and yo are points to establish the equation with and are constant
Thought it would be lot easier with the method I showed? D: \[y=mx+b\]\[5=7(-6)+b\]\[5=-42+b\]\[b = 5--42\]\[b=47\] Then plug everything back \[y=mx+b\]\[y =7(the slope)x + 48\]\[y=7x+47\]
got a spurious "8" in there
those 8s can be tricky
Thanks Zep, your procedure is simple compared to amistre but thank you both of you :)
|dw:1336081254283:dw| No offence, @amistre64, just a joke :P Np ;)
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