Question

How do i find the period of this function?
y=cos 1/3x

Answer 1

period= 2pi/b

Answer 2

where is b?

Answer 3

2pi/1/3 so yall gotta multiply 2pi by tha reciprocal its 6pi so yall got 1/3 of the curve in 1 interval

Answer 4

b=1/3

Answer 5

18.84 correct ?

Answer 6

for the period? no.

Answer 7

6pi

Answer 8

2∏÷1/3

Answer 9

therefore multiply 2∏ by the reciprocal of 1/3. 2∏×3

Answer 10

yeah that's equal 6pi <---

Answer 11

but how to graph ?

Answer 12

yes thus the persiod is 6pi

Answer 13

wolfram it

Answer 14

well i need to know it for the test :|

Answer 15

how to graph y=cos1/3x guys ?

Answer 16

use wolfram.com

Answer 17

period=2pi/coefficient in front of x. amplitude=whatever trig function is multiplied by.

Answer 18

\[\cos (1/3)x=\cos (2\pi ft)\]
Where \[2\pi f\]is the angular frequency
\[(1/3)x=2\pi ft\]
\[f=x/(6\pi t)\]
Period = T = 1/f
\[T=(6\pi t)/x\]

Answer 19

thats just a complicated way of explaining that and it uses a physics formula that isnt needed for trig

Answer 20

do you know the easier way to draw this graph ?

Answer 21

What is your answer for the period Redlinl?

Answer 22

2pi/coefficient in front of x

Answer 23

graph it pleaseeeeeeee

Answer 24

lol =.=