Question

k so how do i get the antiderivative of tan^2x?

please just hints only, im really trying to learn this stuff haha

Answer 1

its integral of tan^2(x) if that is clearer sorry

Answer 2

Hint: \(\tan^2x=\sec^2x-1\)

Answer 3

start with\[\sin^2x+\cos^2x=1\]and get tan^2 out of it

Answer 4

ok blockcolder went a step ahead of me, but same idea

Answer 5

ok! so do i just sup sec^2x-1 and take the integral of that

Answer 6

that would work, wouldn't it?

Answer 7

lol

Answer 8

yes i do think that would work

Answer 9

for the integral of (sec^2(x) - tan^2(x))dx i got (tan(x)-tan(x)-x) is that right?

Answer 10

a separate integral?

Answer 11

@m.auld64 do you still need help?