Question

Help, please?
(Multiplying Rational Expressions)
5x over 2x-17x(squared)-9x times 4x-20x-144 over 20.
Any/all help appreciated c: Will re-type the problem in the comments section for easier viewing.

Answer 1

\[5x \over 2x-17x ^{2}-9x\] times \[4x-20x-144 \over 20\]

Answer 2

Also, the book's answer is \[x+4 \over 2x+1\] if that helps any.

Answer 3

Factor the numerator in the second fraction. In the first fraction, factor the denominator. Looks like they want you to do both by group factoring.

Answer 4

Thanks for the help. Doing that now.

Answer 5

The first fraction, in the denominator, ends in -9, so you will probably take a number out with a multiple of 3. The second is -144, so 12 will probably go with it.

Answer 6

Got it, thanks. Was stuck there.

Answer 7

Should I simplify the second equation? I can't seem to factor it properly using my factoring method.

Answer 8

Did you get something like -4x-8x-12x-144? Factor from there, reduce both equations, what you factored in each should cancel out.

Answer 9

I didn't get that answer for the second one; let me try something else. For the first equation, I got (2x+x)(x-9x) when I factored. Should I be doing something different?

Answer 10

Actually, looking at the problem again you should probably do something like this.\[5x(4x-20x-144) \over20(2x-17x^2-9x)\]

Answer 11

And I should factor from there?

Answer 12

First distribute and then factor the numerator and denominator, then see if you can reduce out some factors.

Answer 13

I can't seem to find a solution, but thank you both for your assistance.

Answer 14

\(2x−17x^2−9x\)
Let's try to factor this, what numbers product gives 2*-9 and sum is -17?

Answer 15

Wait wait, I made a mistake there, but, are you sure that's 17x^2 and not 2x^2?

Answer 16

Herp derp, ignore everything I said.
\(2x−17x^2−9x=-7x-17x^2=x(-7-17x)\)