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OpenStudy (anonymous):
2^x=16x
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OpenStudy (asnaseer):
sorry is your question \(2^x=16\)?
OpenStudy (asnaseer):
or is it really \(2^x=16x\)?
OpenStudy (anonymous):
yes
OpenStudy (asnaseer):
which one? first expression or second expression that I typed?
OpenStudy (asnaseer):
or is it: \(2^x=16^x\)?
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OpenStudy (anonymous):
the second one
OpenStudy (asnaseer):
and which method(s) have you been asked to use to solve this?
OpenStudy (anonymous):
in used log but i couldnt.a friend of mine used titeration
OpenStudy (asnaseer):
have you used the Newton-Raphson method of iteration?
OpenStudy (asnaseer):
if not, I would urge you to double check your question as (if you should be using logs), I believe it is probably more like:\[2^x=16^x\]
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OpenStudy (turingtest):
try converting 16 into a power of 2
OpenStudy (turingtest):
then apply the exponent rule\[\large(x^a)^b=x^{ab}\]after which you will have a common base, and so can take a logarithm
OpenStudy (turingtest):
..if asnaseer is right, but that seems trivial
OpenStudy (maheshmeghwal9):
2^x=16x\[\implies \color{red}{2^x=16x.}\]
OpenStudy (theviper):
It should be like this
\[2^x=16^x\]
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