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Mathematics 21 Online
OpenStudy (anonymous):

2^x=16x

OpenStudy (asnaseer):

sorry is your question \(2^x=16\)?

OpenStudy (asnaseer):

or is it really \(2^x=16x\)?

OpenStudy (anonymous):

yes

OpenStudy (asnaseer):

which one? first expression or second expression that I typed?

OpenStudy (asnaseer):

or is it: \(2^x=16^x\)?

OpenStudy (anonymous):

the second one

OpenStudy (asnaseer):

and which method(s) have you been asked to use to solve this?

OpenStudy (anonymous):

in used log but i couldnt.a friend of mine used titeration

OpenStudy (asnaseer):

have you used the Newton-Raphson method of iteration?

OpenStudy (asnaseer):

if not, I would urge you to double check your question as (if you should be using logs), I believe it is probably more like:\[2^x=16^x\]

OpenStudy (turingtest):

try converting 16 into a power of 2

OpenStudy (turingtest):

then apply the exponent rule\[\large(x^a)^b=x^{ab}\]after which you will have a common base, and so can take a logarithm

OpenStudy (turingtest):

..if asnaseer is right, but that seems trivial

OpenStudy (maheshmeghwal9):

2^x=16x\[\implies \color{red}{2^x=16x.}\]

OpenStudy (theviper):

It should be like this \[2^x=16^x\]

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