2^x=16x
sorry is your question \(2^x=16\)?
or is it really \(2^x=16x\)?
yes
which one? first expression or second expression that I typed?
or is it: \(2^x=16^x\)?
the second one
and which method(s) have you been asked to use to solve this?
in used log but i couldnt.a friend of mine used titeration
have you used the Newton-Raphson method of iteration?
if not, I would urge you to double check your question as (if you should be using logs), I believe it is probably more like:\[2^x=16^x\]
try converting 16 into a power of 2
then apply the exponent rule\[\large(x^a)^b=x^{ab}\]after which you will have a common base, and so can take a logarithm
..if asnaseer is right, but that seems trivial
2^x=16x\[\implies \color{red}{2^x=16x.}\]
It should be like this \[2^x=16^x\]
Join our real-time social learning platform and learn together with your friends!