Question

What is the value of x, when x2 + 5 = 21?

Answer 1

x^2+5=21 -> x^2=16.
So, x=4 or x=-4

Answer 2

take away five from both sides then take the square root

Answer 3

well the first thing to do is isolate x
x^2 + 5 = 21
x^2 = 21 - 5
x^2 = 16
Now to take out the ^2 you find the square root
x^2 = 16
x = sqrt(16
x = 4 or x = -4; since it will result the same

Answer 4

Thankk youu : )