Question

Please help answer this problem: (image attached)

Answer 1

the function is f(x) = 5x^2

then f'(x) = 10x

f'(3) = 30

Answer 2

How did you come up with the function?

Answer 3

I looked at x = 3 f(x) = 45.... so I chose 5x^2 substituted x+ 2.8 and came up with 39.2

also its increasing over the domain made me think about a quadratic...

Answer 4

Is there a way to come up with the function without just looking at it? What if it was a bit harder to come up with?

Answer 5

you can plot the points (x,f(x)) on the number plane... thats an easy way

Answer 6

Thanks