Question

How do I solve for a??
114=(180)(a^-2)+34

it is suppose to be 3/2

any help on how to get that?

Answer 1

\(\begin{array} \ 115 &= 180(a^{-2}) +34 \\ 115-34 &=180(a^{-2}) \\ 81 &= 180(a^{-2}) \\ 0.45 &=a^{-2} \\ \end{array}\)

Answer 2

might want to start with \(115=\frac{180}{a^2}+34\) but it makes no difference,

Answer 3

where did u get 115?

Answer 4

Yeah, right, excellent advice ;D

Answer 5

Oh, it's 114..
\(\begin{array} \ 80 \div 180&= (a^{-2}) \\ \frac{4}{9} &=1 \div a^2 \\ 1 \div \frac{4}{9} &= a^2\\ \sqrt{2.25} &= a \\ \frac{3}{2} &= a\end{array}\)

Answer 6

thanks! i understand now. yall ROCK