Question

Graph and label center and 4 points
61x^(2)+9y^(2)=144

Answer 1

just divide both sides by 144....
to get it in standard form....

the center of this ellipse is 0,0.

replace x=0 to get your y-intercepts
replace y=0 to get your x-intercepts

Answer 2

thank you that has been confusing me

Answer 3

do you have the 4 points then ?

Answer 4

not yet just started working on it

Answer 5

so i did\[16x ^{2}+9y ^{2}= 144\]\[16x ^{2}+9y ^{2}/144 =144 /144\]\[x ^{2}/9+y ^{2}/16=1\]center of (0,0)\[\sqrt{9}=3 \]so Right and Left 3\[\sqrt{16}=4\] up and down 4
gives me point at (-3,0),(3,0),(0,4),(0,-4)

Answer 6

hmm... the problem in your original post says 61... but you did the process correctly anyway...

Answer 7

lol sorry it was 16

Answer 8

sawright... you got it right... good work man... :)

Answer 9

thank you again