Graph and label center and 4 points
61x^(2)+9y^(2)=144

Question

Graph and label center and 4 points
61x^(2)+9y^(2)=144

anonymous · Answer

just divide both sides by 144....
to get it in standard form....

the center of this ellipse is 0,0.

replace x=0 to get your y-intercepts
replace y=0 to get your x-intercepts

boxman61 · Answer

thank you that has been confusing me

anonymous · Answer

do you have the 4 points then ?

boxman61 · Answer

not yet just started working on it

boxman61 · Answer

so i did$$16x ^{2}+9y ^{2}= 144$$$$16x ^{2}+9y ^{2}/144 =144 /144$$$$x ^{2}/9+y ^{2}/16=1$$center of (0,0)$$\sqrt{9}=3 $$so Right and Left 3$$\sqrt{16}=4$$ up and down 4
gives me point at (-3,0),(3,0),(0,4),(0,-4)

anonymous · Answer

hmm... the problem in your original post says 61... but you did the process correctly anyway...

boxman61 · Answer

lol sorry it was 16

anonymous · Answer

sawright... you got it right...  good work man... :)

boxman61 · Answer

thank you again