Question

solve a-8/a+5=a^2-12/a+5

Answer 1

uhmm where does the problem start?

Answer 2

a-8/a+5 = a^2-12/a+5

Answer 3

a=2

Answer 4

\[\large \frac{a-8}{a+5} = \frac{a^2 - 12}{a+5}\] is that right?

Answer 5

[a = 2], [a = -1/2+(1/2*I)*sqrt(7)], [a = -1/2-(1/2*I)*sqrt(7)]

Answer 6

yes

Answer 7

well if you cross multiply... \[\large \frac{\cancel{(x+5)}(a-8)}{\cancel{x+5}} = a^2 - 12\]

\[a - 8 = a^2 - 12\]
put all of them on one side

\[\large a^2 - a - 12 + 8 = 0\]
\[\large a^2 -a -4 = 0\]

Answer 8

you can use completing the square or quadratic formula

Answer 9

a = 2 is wrong..
factor, a−8=a2−12
simplify and use quadratic formula to get:
\[a = \frac{(1\pm \sqrt{17})}{2}\]