What polynomial has roots of –1, –2, and 3?

a. x^3 + 6x^2 + 11x + 6
b. x^3 – x^2 – 5x + 2
c. x^3 + 2x^2 – 7x + 2
d. x^3 – 7x – 6

Please can u also tell me how?

Question

What polynomial has roots of –1, –2, and 3? 

a. x^3 + 6x^2 + 11x + 6
b. x^3 – x^2 – 5x + 2
c. x^3 + 2x^2 – 7x + 2
d. x^3 – 7x – 6

Please can u also tell me how?

auctoratrox · Answer

D. take (x+1)(x+2)(x-3)=...

callisto · Answer

since it has roots of -1, -2, 3
f(x) = (x+1)(x+2)(x-3)
Now, expand the terms, can you do it?

anonymous · Answer

roots of -1, -2, 3
x=-1 -> (x+1)
x=-2 -> (x+2)
x=3 -> (x-3)
(x+1)(x+2)(x-3)
x^3 – 7x – 6

Alternately, you can plug in -1, -2, 3 on all of them and find which one makes all of them 0.

anonymous · Answer

why do u change -1 to 1 and so on?

jim_thompson5910 · Answer

He did this


x= - 1, x = -2, or x = 3

x+1 = 0, x+2 = 0, or x -3 = 0

(x+1)(x+2)(x-3) = 0... He used the zero product property here


From there, he expanded and simplified the left side

anonymous · Answer

ok, i get it now... thanks everyone so much!

anonymous · Answer

i got d... great!