Question

log(7)3=K
7^(3y-1)=21

howw

Answer 1

\[\log _{7}3=k\]
\[7^{3y-1}=21\]

Answer 2

What's the question? Get k and y?

Answer 3

y in terms of K

Answer 4

sorry

Answer 5

\[7^{3y-1}=21\]
\[7^{3y-1}=7*3\]
\[7^{3y-2}=3\]
\[log{7^{3y-2}}=log{3}\]
\[(3y-2)log{7}=log{3}\]
\[(3y-2)=log{3}/log(7)\]
\[3y-2=log_7{3}\]
\[3y-2=k\]
\[3y=k+2\]
\[3y=(k+2)/3\]

Answer 6

Last one is \[y=(k+2)/3\]