Question

solve
log(2x+20)=1
process please, trying to learn

Answer 1

log(x) = y
is the same as
x = 10^(y)

thus
10^(log(2x+20))=10^(1)
=
2x+20 = 10^(1)
=
2x+20 = 10

Answer 2

\[2x+20=10\]\[2x=-10\]\[x=-5\]

Answer 3

just remembered that...thank you

Answer 4

just make both sides exponents to the power of 10 the logarithm will cancel out because it is base 10 and you can solve

if you had

ln(x) = y
or
log_8(x) = y
then we would have to put

e^(ln(x)) = e^(y)
=
x = e^y

and the other example with log base 8

would be

8^y = x