Question

Find general solution in implicit form

Answer 1

\[dy/dx= (2cosx-3) \exp ^{(-3x+2sinx)/6)} y ^{5/6} (y>0)\]

Answer 2

\[ \int \frac{dy}{(2 \cos x - 3)e^{\frac{-3x+2sinx}{6}}} = \int \frac{dt}{y^{5/6}} + C\]

Answer 3

I how i integrate the left side of the equation.

Answer 4

I have got stuck on that.

Answer 5

Assume (-3x+sin x)/6 = u

Answer 6

what method should I use? Then I can try and solve it myself.

Answer 7

Substitution

Answer 8

Thanks for all the help

Answer 9

that is a wrong way !!!