Question

help me with logs, log6 x = 1/4log6 16

Answer 1

ok so according to the law of logs
\(\large log_ab^c=c(log_ab) \)
this means that \(\large \frac{1}{4}log_616=log_616^{\frac{1}{4}}=log_62 \)

so we dealt with the right side of the equation, let's put it together

\(\huge log_6x=log_62 \)
we can safely say that \(\huge x=2 \)