Question

Find the area below the graph of...

Answer 1

\[y=(1-2cosx)(3+2cosx)e ^{1/2x+cosx}\]

0 (less then and equal to) x (which is less and equal to) 2pi

Answer 2

1/2x+cosx= (1/2)x +cosx ?

Answer 3

should be (1/2)x + cosx

Answer 4

\[\large{\int\limits_{0}^{2 \pi}(1-2cosx)(3+2cosx)e^{(\frac{1}{2}x+cosx)}dx}\]

Answer 5

Yes

Answer 6

\[\int\limits\limits\limits (1−2cosx)(3+2cosx)e ^{(x/2)+cosx} dx = -4e^{(2cosx+x)/2}sinx-2e^{(2cosx+x)/2}+C\]