Question

I need help solving for x.

Answer 1

This is it:\[a^2x+(a-2)=(a+2)x\]Not sure where to start..

Answer 2

I have the answer but I don't know how to get it:\[x=\frac{-1}{a+1}\]

Answer 3

\[a ^{2}x+a-2=ax+2x\]
multiply them first then put all the a's to one side..

Answer 4

Well I shouldn't say not sure where to start I guess.. I got:
\[a(ax−x+1)=x(x+2)\]This is where I'm actually stuck at.

Answer 5

how about if we do.. \[a ^{2}x+a-2=ax+2x\]

Answer 6

\[a ^{2}x-a-ax=2x+2\]
\[a ^{2}x-ax-2x=2-a\]
\[x(a ^{2}-a-2)=2-a\]

Answer 7

here solve for x!!

Answer 8

x=2-a/a^2-a-2 -> factor the denominator a^2-a-2
x= - (-2+a)/(a+1)(a-2)
x=-1/(a+1)

Answer 9

Yea I had just tried that way before asking on here and didn't think about factoring the a^2-a-2 so thats where I stopped and tried a different way. Thanks though

Answer 10

welcome.. :)