I need help solving for x.

Question

lasttccasey · Answer

This is it:$$a^2x+(a-2)=(a+2)x$$Not sure where to start..

lasttccasey · Answer

I have the answer but I don't know how to get it:$$x=\frac{-1}{a+1}$$

anonymous · Answer

$$a ^{2}x+a-2=ax+2x$$ 
multiply them first then put all the a's to one side..

lasttccasey · Answer

Well I shouldn't say not sure where to start I guess.. I got:
$$a(ax−x+1)=x(x+2)$$This is where I'm actually stuck at.

anonymous · Answer

how about if we do.. $$a ^{2}x+a-2=ax+2x$$

anonymous · Answer

$$a ^{2}x-a-ax=2x+2$$
$$a ^{2}x-ax-2x=2-a$$
$$x(a ^{2}-a-2)=2-a$$

anonymous · Answer

here solve for x!!

anonymous · Answer

x=2-a/a^2-a-2 -> factor the denominator a^2-a-2
x= - (-2+a)/(a+1)(a-2)
x=-1/(a+1)

lasttccasey · Answer

Yea I had just tried that way before asking on here and didn't think about factoring the a^2-a-2 so thats where I stopped and tried a different way. Thanks though

anonymous · Answer

welcome.. :)