Question

What is the vertex for the graph of the quadratic function f(x)=1/4(x+2)^2-9

Answer 1

(-2,-9)

Same reason as your previous question.

Answer 2

Ok please explain. Vertex form is y=a(y-h)^2+k

Answer 3

(h,k)

Answer 4

ok. now how do i work that out?

Answer 5

it should be : y=a(x-h)^2+k

Answer 6

in the formula foolformath gave
f(x)=1/4(x+2)^2-9
y=a(x-h)^2+k
you can now determine the center w/c is h,k

Answer 7

ok...i see

Answer 8

thank you both