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-4x(-4)^-3
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true? im not sure what you're asking \[\frac{-4x}{-4^3}\]
if you pull a four out of the top you'll get
\[\frac{-4(x)}{(-4)(-4)(-4)}=]\frac{x}{-4^2}=\frac{x}{16}\]
did you want it simplified?
no you multiply not divide
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He divided because the exponent was negative. \[a^{-b} = {1 \over a^b}\]This definition makes sense because it agrees with the following: \[a^b a^{-b} = a^{b - b} = a^0 = 1\]So that answer is correct.
thanks i got it right ::)))))
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