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Two point charges, initially 2 cm apart, are moved to a distance of 10 cm apart. By what factor does the resulting electric force between them change? a. 5 b. (1/5) c. (1/25)
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The answer is C since: \[F=k\frac{q_1q_2}{r^2}\]The key here is to note that the force is proportional to 1/r^2...and you increased r by a factor of 5 in this question.
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