Mathematics
21 Online
OpenStudy (curry):
find an equivalent equation in rectangular form for r-6sin=2coss
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OpenStudy (anonymous):
do you know the substitutions?
OpenStudy (curry):
ye i got to x^2 +y^2=2x+6y but i dont know where to go from there2
OpenStudy (experimentx):
put sin .. = y/sqrt(x^2+y^2) and cos ..= x/sqrt(x^2+y^2) and r = sqrt(x^2+y^2)
and then simplify
OpenStudy (curry):
but the final ansswer should be in rectangular form meaning it hould have no r or anythuing
OpenStudy (experimentx):
yeah ... that's why i am telling you to substitute r's and sines and cosines ... as above
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OpenStudy (curry):
but either way i still end up with x^2 + y^2 = 2x+ 6y can i plz see ur woprk and final anwer
OpenStudy (anonymous):
your answer is correct.
what do you need?
OpenStudy (anonymous):
your answer can be written in standard form for a circle but that's it...
OpenStudy (anonymous):
is that what you want to do?
OpenStudy (curry):
ye
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OpenStudy (curry):
y would it equal 3?
OpenStudy (curry):
i mean t
OpenStudy (anonymous):
ok.. let's start with your equation:
x^2 + y^2 = 2x + 6y
OpenStudy (anonymous):
move everything on that right side over to the left side. can you do that?
OpenStudy (curry):
ye
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OpenStudy (anonymous):
so what do you have?
OpenStudy (curry):
x(x-2)=-y(y-6)
OpenStudy (anonymous):
don't factor...
OpenStudy (anonymous):
and your right side should be 0
OpenStudy (curry):
x^2 - 2x + y^2 -6y
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OpenStudy (anonymous):
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