Question

Rewrite the expression (cos^2x)/(1+sinx) so that there is no fraction.

Answer 1

\[\frac{1-\sin^2x}{1+\sin^2x}\]
Remember difference of squares?
\[\frac{(1-\sin x)(1+\sin x)}{1+\sin x}\]
can you solve now?

Answer 2

is it 1/sinx = cscx?

Answer 3

1+sin x cancels out from both numerator and denominator and so leaving you behind with 1-sin x

Answer 4

Got it! Thanks!