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Mathematics 20 Online
OpenStudy (anonymous):

whats a contradictory statement of "all men are honest,".

OpenStudy (anonymous):

all men are dishonest

OpenStudy (apoorvk):

"All men are not honest". basically if a statement is given that is valid for all cases, the contradictory statement for it would one where the theory in the statement is that the rule is violated for ATLEAST for case. So, if p=All men are honest. ~p=Not all men are honest. -OR- All men are not honest

OpenStudy (anonymous):

thanks that what i got you guys!!!!!

OpenStudy (apoorvk):

@kevinkeegan are you sure? I am doubtful about what you say.

OpenStudy (anonymous):

lol whatever

OpenStudy (apoorvk):

There is a difference between "all men are dishonest' and "not all men are honest". The later means that "tere is ATLEAST one dishonest person". the former means that "all are dishonest"

OpenStudy (apoorvk):

*there

OpenStudy (anonymous):

so could it also be some men are dishonest?

OpenStudy (lgbasallote):

your teacher is a woman isnt she =_=

OpenStudy (apoorvk):

LOLLL!!

OpenStudy (apoorvk):

Nope not 'some' - I know that there all aren't honest. We don't know how many - 1, 2, 3, 100, or everyone's dishonest - no we don't know that - but not all are honest - 'there exists atleast one man who is not honest" - this is also a valid contradiction.

OpenStudy (blockcolder):

\[p(x) - \text{A person is a man.}\\ q(x) - \text{A person is dishonest.}\\ \text{All men are dishonest} \equiv \forall x(p(x) \to q(x))\\ \text{Negation is} \exists x(p(x) \wedge \neg q(x))\] Therefore, a contradicting statement is "At least one man is not dishonest (honest)."

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