A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?

Question

stormfire1 · Answer

Use $$V_f=V_i+at$$$$19.2m/s=0m/s+(3.2m/s^2)(6.0s)$$

amistre64 · Answer

wouldnt "downhill" give us a velocity with a negative indicating direction?

anonymous · Answer

i dont hve a calculatorr and i dont know this .. can u please helpp

amistre64 · Answer

you should have pencil and paper, and the capacity to multiply

otherwise use your computer or even the google search engine functions as a calculator

stormfire1 · Answer

@amistre64: I didn't really like the question because It didn't give any info on the height & slope of the hill! I just went with the magnitude of the velocity since I think that was the intent of the question.

stormfire1 · Answer

I guess for your final answer it should be -19.2 m/s

anonymous · Answer

thnku