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Find the slope of the line tangent to the curve at the given value of x f(x)=x^2+5x at x=-6
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f'(x)=2x+5 The question is to find f'(-6), so plug in -6 above.
-66? That seems off
2*(-6)+5
isnt it plus 5x?
I meant to put -6 in the f'(x), not f(x)
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f'(x) is the slope of the line tangent to the curve at x.
so its -31?
f(x)=x^2+5x f'(x)=2x+5 f'(-6)=2*(-6)+5=-12+5=-7
oh i see. sorry i was confused. so -7 would be the slope then right
Yep!
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alright thanks!
Welcome^^
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