Question

Evaluate the indefinite integral.
integral of 6x/x^4+1 dx
Please help me! Thanks!

Answer 1

u-sub

u=x^2
du=2xdx
\[3\int\limits \frac{1}{u^2+1} \, du\]

Answer 2

trig substitution

Answer 3

u=tan(y)

\[y=\tan^{-1}u\]
Integrate
\[3 \tan ^{-1}(u)+c\]
\[3 \tan ^{-1}\left(x^2\right)+c\]

Answer 4

Hmm.. I see.. That's how you do it! Thanks so much! I've been doing this for days and I couldn't get it.. I see where I got confuse.. Thanks so much! :D

Answer 5

yw