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Mathematics 17 Online
OpenStudy (anonymous):

2^(x-4)+10=22

OpenStudy (anonymous):

you did see that whole last post didn't you?

OpenStudy (anonymous):

I didn't =(

OpenStudy (anonymous):

no... i don't mind... :)

OpenStudy (anonymous):

Thank you so much! =) =)

OpenStudy (anonymous):

solve again... subtract 10 both sides. take natural log both sides...

OpenStudy (anonymous):

2^(x-4)=12

OpenStudy (anonymous):

natural log both sides...

OpenStudy (anonymous):

ln2^(x-4)=ln12

OpenStudy (anonymous):

i'm getting ahead of myself... sorry.

OpenStudy (anonymous):

Thats okay! =)

OpenStudy (anonymous):

ok.. good. utilizing the properties of logs, you can bring the exponent of (x-4) down to ln2

OpenStudy (anonymous):

Which would bring me to (x-4)ln2 = ln12, right?

OpenStudy (anonymous):

yes...:)

OpenStudy (anonymous):

now divide by ln2 both sides

OpenStudy (anonymous):

Which would make it (x-4) = ln6

OpenStudy (anonymous):

the right side should be (ln12)/(ln2)

OpenStudy (anonymous):

So (x-4)=(ln12)/(ln6)

OpenStudy (anonymous):

yep... now add 4 to both sides and you'll have your x =

OpenStudy (anonymous):

x= (ln12)/(ln2)+4

OpenStudy (anonymous):

that's the exact form... if you want an approximation, punch that into your calculator.

OpenStudy (anonymous):

Once rounded I got 7.58

OpenStudy (anonymous):

lemme double check again...

OpenStudy (anonymous):

ok.. that's what i got.. 7.5849 lemme stick it back into the equation...

OpenStudy (anonymous):

ok... it works... :)

OpenStudy (anonymous):

YAY! =) Thank you!

OpenStudy (anonymous):

yw...

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