Mathematics
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OpenStudy (anonymous):
2^(x-4)+10=22
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OpenStudy (anonymous):
you did see that whole last post didn't you?
OpenStudy (anonymous):
I didn't =(
OpenStudy (anonymous):
no...
i don't mind... :)
OpenStudy (anonymous):
Thank you so much! =) =)
OpenStudy (anonymous):
solve again...
subtract 10 both sides. take natural log both sides...
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OpenStudy (anonymous):
2^(x-4)=12
OpenStudy (anonymous):
natural log both sides...
OpenStudy (anonymous):
ln2^(x-4)=ln12
OpenStudy (anonymous):
i'm getting ahead of myself... sorry.
OpenStudy (anonymous):
Thats okay! =)
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OpenStudy (anonymous):
ok.. good. utilizing the properties of logs, you can bring the exponent of (x-4) down to ln2
OpenStudy (anonymous):
Which would bring me to (x-4)ln2 = ln12, right?
OpenStudy (anonymous):
yes...:)
OpenStudy (anonymous):
now divide by ln2 both sides
OpenStudy (anonymous):
Which would make it (x-4) = ln6
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OpenStudy (anonymous):
the right side should be (ln12)/(ln2)
OpenStudy (anonymous):
So (x-4)=(ln12)/(ln6)
OpenStudy (anonymous):
yep... now add 4 to both sides and you'll have your x =
OpenStudy (anonymous):
x= (ln12)/(ln2)+4
OpenStudy (anonymous):
that's the exact form... if you want an approximation, punch that into your calculator.
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OpenStudy (anonymous):
Once rounded I got 7.58
OpenStudy (anonymous):
lemme double check again...
OpenStudy (anonymous):
ok.. that's what i got.. 7.5849
lemme stick it back into the equation...
OpenStudy (anonymous):
ok... it works... :)
OpenStudy (anonymous):
YAY! =) Thank you!
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OpenStudy (anonymous):
yw...