Question

simplify the radical expression.
5. √250h^4k^5

6. √14q x 2√4q




7. √63x^15y^9/7xy^11




8. √3+4√3
5√6
5√3
3√6
3√3




9. 2√6+3√96
14√6
14√96
5√96
50√6



10. (8 +√11 )(8 –√11 )
53
75 + 16√11
–57
64 + √11

Answer 1

For (5), is this the question?
\[\sqrt{250h^4k^5}\]

Answer 2

yea

Answer 3

Simple foil out question 11, remembering that:

\[\sqrt{11}\times \sqrt{11}=11\]

Answer 4

\[\sqrt{250h^4k^5} = \sqrt{25 \times 10 (h^2)^2(k^2)^2k} = \sqrt{(5h^2k^2)^2\times 10k}\]\[ =\sqrt{(5h^2k^2)^2}\times \sqrt{10k} =? \]

Answer 5

You should remember that\[\sqrt{a} \times \sqrt{b}=\sqrt{ab}\]
and \[\sqrt{a} \times \sqrt{a}=a\]

Answer 6

25hk√10k

Answer 7

Nope ._.
\[\sqrt{a^2} =a\]
Can you try again?

Answer 8

5√10h^4k^5

Answer 9

Nope....
try a =5h^2k^2
what do you get?

Answer 10

hk√125

Answer 11

Incorrect again....
\[\sqrt{(5h^2k^2)^2} \times \sqrt{10k} = 5h^2k^2 \sqrt{10k}\]
Since 5h^2k^2 are ALL squared...
Got it?

Answer 12

so did i get it right

Answer 13

Nope ._.

Answer 14

5h^2k^2√10k

Answer 15

Yes. this is right

Answer 16

thanks

Answer 17

For (6) is this the question?
\[\sqrt{14q} \times 2\sqrt{4q}\]

Answer 18

yea

Answer 19

I have 5 and 6.

Answer 20

\[\sqrt{14q} \times 2\sqrt{4q}=\sqrt{14q} \times 2\sqrt{2^2q}=\sqrt{14q} \times 4\sqrt{q}\]\[=4\sqrt{(14q)\times q} = 4\sqrt{14q^2} = ?\]

Answer 21

can you the answers

Answer 22

give the

Answer 23

Can you solve it yourself first?

Answer 24

I didn't mean I didn't want to help you.. but I think you should at least try to do it once first...