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divide and check (36t^6-27t^5-9t^20/(-9t^2)
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Is this your equation? \[\frac{36t^6-27t^5-9t^{20}}{-9t^2}\]
yes
wait -9t^2 not 9t^20
ok then this?\[\frac{36t^6-27t^5-9t^{2}}{-9t^2}\]
\[\frac{36t^6-27t^5-9t^{2}}{-9t^2}=\frac{36t^6}{-9t^2}+\frac{-27t^5}{-9t^2}+\frac{-9t^2}{-9t^2}\] can you simplify this?
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yes
yes
So what do you get for the simplified version?
4t^3+3t^2+1t^1 then 74 i think
is this correct
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It isn't what I got. \[\frac{36t^6}{-9t^2}=-4t^4\] I'm not sure how you got \[4t^3\]
\[\frac{-27t^5}{-9t^2}=3t^3\]\[\frac{-9t^2}{-9t^2}=1\]
\[-4t^4+3t^3+1\]
i didn't subtract almost got it thank you very much
so this is my answer
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