Question

can anybody show me step-by-step on how to find the value of the unknown variables? please..


problem:

find value of x, y, and z.
x+y=24
y+z=26
x+z=28

ASAP. .

Answer 1

put the @ before so he can see it in his notification... I'm trying it out I'll get back to you if I get it

Answer 2

@ishaan94 help. .

Answer 3

ok, I managed to get an answer, but I feel that there should be a much more direct answer, but this is what I got.:

Answer 4

can you please show me?

Answer 5

From algebra we know we can tweak with equations... so:

the 3 normal equations
x+y=24
y+z=26
x+z=28

we get

x=24-y
x=28-z
y=24-x
y=26-z
z=26-y
z=28-x

now, to find out a little more information, I played with it again.

since x=24-y and 28-z then,

24-y=28-z

so then this gives when we move to integers to combine like terms in one side;
-4-y=z
or
4+y=z
which means that z is 4 more units bigger than whatever y is...

now, y=26-z = 24-x
26-z=24-x
z=2+x
z is 2 more than whatever x is

and finally,
z=26-y=28-x
26-y=28-x
2+y=x
so x is 2 units bigger than whatever y is

so... once again the info

x is 2 more than y
z is 2 more than x
z is 4 more than y

from there we just see for first equation

y+x=24
and from the information obtained we get y=11 and x= 13

and now that you know these, getting z is a breeze

Answer 6

how about the value of z?

Answer 7

well since we know that z is 2 more than x and 4 more than y all you have to do is add 2 to x or 4 to y to get z...

which is 15

11+4=15
13+2=15

so z=15

Answer 8

and you can double check by plugging it into the formulas

Answer 9

thanks. . .

Answer 10

yea no problem, I do believe this was the primeval methods used to solve this equation lol.. but I don't know any modern ones... except using matlab, which is a software you might learn to use if you take engineering courses... if you find out a shorter way to do it.. let me know

Answer 11

lol. . the question is, if i can? lol. . but' anyway thanks again!