Question

Eleven dimes dated 1989 through 1999 are tossed. Find the probability of the event.
9. Tails on all but one dime

Answer 1

\(\Large \color{MidnightBlue}{\Rightarrow [\matrix{9 \\8}] }\)

Answer 2

\(\Large \color{MidnightBlue}{\Rightarrow {9! \over8!} }\)

Answer 3

And actually, that'd become 1 over that.

Answer 4

That leaves just 9 for us.


\(\Large \color{MidnightBlue}{\Rightarrow {1 \over 9} }\)

Answer 5

@PaxPolaris How'd you get that one -_-

Answer 6

sorry 11 dimes (not 10) so :
\[\huge= {11 \over 2^{11}}\]

Answer 7

11 total ways to arrange 1 head and 10 tails

out of 2^11 total possibilities

Answer 8

i got 1/2048

Answer 9

11/2048...

the 1st coin could be the head, or the 2nd, or the 3rd..... or the 11th