Identify the 19th term of a geometric sequence where a1 = 14 and a9 = 358.80. Round the common ratio and 19th term to the nearest hundredth. a19 ≈ 9,195.53 a19 ≈ 31,035.73 a19 ≈ 13,185.66 a19 ≈ 20,690.49
common ratio \[\sqrt[8]{358.80/14} =?\]
to be honest idk how to solve that?
First, solve 358.80/14 What do you get?
25.6285714
Now, use your calculator to solve \[\sqrt[8]{25.62857143}\]
1.4999975505
Now, r=common ratio a19 = a1 [r^(n-1)] = 14 (1.49999755 ^ (19-1)] = 14 (1.49999755 ^ (18)] = ?
n is the no of term
20689.878152782416417171686483306764932120668078659492
would it be a19 ≈ 20,690.49? thats the closest answer
would it be a19 ≈ 20,690.49? thats the closest answer
Isn't it 20689.88? I don't know :|
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