The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X. http://go.flvs.net/courses/1/flvs_57_3641_12676/ppg/respondus/pool_Geom_3641_0810_06/image0044e68c63e.jpg What is the measure of angle ACB? Answer 16° 23° 32° 46°
In the figure the inscribed angle of 32 degrees yields an arcAngle of 64 degrees. ( http://www.mathwarehouse.com/geometry/circle/inscribed-angle.php) If you know both arcAngles subtended by two secants you can use the following equation: exteriorAngle = (farArc - nearArc)/2 ( http://www.mathwarehouse.com/geometry/circle/tangents-secants-arcs-angles.php) In this case it would be 46 degrees
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