how would i solve this question?

Question

anonymous · Answer

attachment

anonymous · Answer

Take the natural log of each side and you end up with:
$$\ln(49)^x=\ln(\sqrt7)^{2x+6}$$
following log rules we can obtain:
$$xln(49) = (2x+6)\ln(\sqrt7)$$

would you be able to solve it from here?

anonymous · Answer

no, my lesson did a terrible job at explaining these problems.

anonymous · Answer

49 = 7^2
sqrt ( 7) = 7 ^ (1/2)
Can you plug them in?

anonymous · Answer

@wowbriana Do you still need help?

anonymous · Answer

what do i have to plug in?

jhonyy9 · Answer

yes Chlorophyll this is the right way sure

anonymous · Answer

Wherever 49 and sqrt(7), plug the correspondence values in, pls!

anonymous · Answer

what happens to the 2x+6 ?

anonymous · Answer

Leave it there!

anonymous · Answer

Could you post your steps here?

anonymous · Answer

i dont even know how to solve this, so i cant put any steps.

anonymous · Answer

That's why I ask you FOLLOW the instruction!

anonymous · Answer

your asking me toplug the correspondence values in but i dont know what they are

anonymous · Answer

Did you look at your question?

anonymous · Answer

yes i did, which is why i need help.

jhonyy9 · Answer

briana how you think a^x =a^2 when will be equales ?

anonymous · Answer

What's relationship between these 2 numbers"
49  and sqrt ( 7) ?

anonymous · Answer

7.

anonymous · Answer

49 = 7  ???

jhonyy9 · Answer

briana this is just for you can understanding how you need to solve your exersice

anonymous · Answer

yeah 7 is the square root of 49

anonymous · Answer

sqrt ( 7 ) = 7 to what power?

anonymous · Answer

1?

anonymous · Answer

Note:  sqrt = 1/2
->sqrt ( 7 ) = 7 to what power?

anonymous · Answer

Seem like it'll take time for you to learn the concept:
49 = 7^2
sqrt ( 7) = 7 ^ (1/2)
Can you plug them in?